Using a Makefile as an Xcode target
By cej38 at Tue, Mar 13 2007 4:20pm |
I am using Xcode 2.4.1.
I have several programs that I, and others, work on that must run on a variety of Unix-like systems. We use a Makefile to control the compilation process.
As I go through the steps specified by an Apple Development document (URL given below), get stuck at item 6, where we are told to choose the “GNU Make Target." I don't see this in my list of the choices. The document says to upgrade if you don't see this choice.
As far as I can tell 2.4.1 is the latest version, nor can I find anything that tells how to actually Upgrade.
Any help would be appreciated.
http://developer.apple.com/documentation/Porting/Conceptual/PortingUnix/preparing/chapter_3_section_4.html
Now it's "External Build System"
The options changed in Xcode, although I can't remember what version.
It's now called "External Build System"
http://developer.apple.com/documentation/DeveloperTools/Conceptual/XcodeUserGuide/Contents/Resources/en.lproj/05_02_bs_targets/chapter_30_section_3.html
Cheers,
-Geoff
make: execvp: gfortran: Permission denied
I set the target to use the Makefile. But it fails to compile from within Xcode (though it does so nicely by typeing "make" in a terminal).
The error that I receive is "make: execvp: gfortran: Permission denied."
The settings that I have for the target are:
Product name: [program name]
Build Tool: /usr/bin/make
Arguments: $(ACTION)
Directory: [Path to the folder containing the Makefile]
Build Settings:
COPY_PHASE_STRIP = NO
GCC_DYNAMIC_NO_PIC = NO
GCC_GENERATE_DEBUGGING_SYMBOLS = YES
GCC_OPTIMIZATION_LEVEL = 0
PRODUCT_NAME = [program name]
I have also tried $<'buildsetting> and $ALL_SETTINGS in Arguments.
Arguments
The solution to my problem was that I needed to change the Arguments field to:
"PATH=/usr/local/bin:/other/paths/bin:$PATH $(ACTION)"
This solution came from Brian Onn in a Apple Mailing Lists post.